JEE Advance - Mathematics (2011 - Paper 1 Offline - No. 3)
The minimum value of the sum of real numbers $${a^{ - 5}},\,{a^{ - 4}},\,3{a^{ - 3}},\,1,\,{a^8}$$ and $${a^{10}}$$ where $$a > 0$$ is
Svar
8
Forklaring
We have $${{{a^{ - 5}} + {a^{ - 4}} + {a^{ - 3}} + {a^{ - 3}} + {a^{ - 3}} + {a^8} + {a^{10}} + 1} \over 8} \ge 1$$
Therefore, the minimum value is 8.